Question

The probability that Kumar will hit a target is given as $\frac{1}{5}$. Then, his probability of at least one hit in $10$ shots is:

• A. $\frac{1}{6^{10}}$
• B. $1-{\left(\frac{4}{5}\right)}^{10}$
• C. $1-\frac{1}{5^{10}}$
• D. $1-\frac{1}{6^{10}}$

Answer 1

Answer: (B)

$1-{\left(\frac{4}{5}\right)}^{10}$

$P\left(A\right)=\frac{1}{5},P\left(\overline{A}\right)=1-\frac{1}{5}=\frac{4}{5}$
$The$ $probability$ $that$ $he$ $will$ $not$ $hit$ $the$ $target$ $in$ $10$ $shots$ $is$ $(\frac{4}{5}{)}^{10}$
$So,$ $probability$ $that$ $atleast$ $once$ $target$ $will$ $be$ $hit$ $=1-(\frac{4}{5}{)}^{10}$