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Question

The probability that out of 5 persons, all having birthday in March, at least two have the same birthday

A
31C5(31)5
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B
(31)531C5(31)5
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C
(31)331C5(31)5
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D
None of these
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Solution

The correct option is B (31)531C5(31)5
Number of days in month of March=31
n(S) = 315
n(A)= at least two have the same birthday
=n(S) Number of ways in which all candidates have the different birthday
=315 - 31C5
P ={
315 - 31C5 }/ 315

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