The probability that out of 5 persons, all having birthday in March, at least two have the same birthday
A
31C5(31)5
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B
(31)5−31C5(31)5
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C
(31)3−31C5(31)5
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D
None of these
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Solution
The correct option is B(31)5−31C5(31)5 Number of days in month of March=31 n(S) = 315 n(A)= at least two have the same birthday =n(S) Number of ways in which all candidates have the different birthday =315 - 31C5 P ={ 315 - 31C5 }/ 315