The probability that sin -1sin x-cos -1 cosy is an integer x- y -1-2-3-4 is A- 3-16B- 1-16C- 15-16D- 1-17

The correct option is A 3/16sin^ 1(sin x)+cos^ 1(cos y) to be integer x ∈[ π/2π/2 ] and y ∈ [0, π]⇒ x =1 and y =1,2,3. required Probability =3/16 ...

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Standard XII

Mathematics

Classical Definition of Probability

The probabili...

Question

The probability that $s i n^{- 1} (s i n x) + c o s^{- 1} (c o s y)$ is an integer $x, y \in$ {1,2,3,4} is

\frac{1}{16}

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\frac{3}{16}

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\frac{15}{16}

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\frac{1}{17}

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Solution

The correct option is B $\frac{3}{16}$
$s i n^{- 1} (s i n x) + c o s^{- 1} (c o s y)$ to be integer $x \in [- \frac{π}{2} \frac{π}{2}]$ and $y \in [0, π] \Rightarrow x = 1$ and y =1,2,3. required Probability = $\frac{3}{16}$

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The probability that sin−1(sinx)+cos−1(cosy) is an integer x,y∈ {1,2,3,4} is

The correct option is B 316sin−1(sinx)+cos−1(cosy) to be integer x∈[−π2π2] and y∈[0,π]⇒x=1 and y =1,2,3. required Probability =316

The probability that $s i n^{- 1} (s i n x) + c o s^{- 1} (c o s y)$ is an integer $x, y \in$ {1,2,3,4} is

The correct option is B $\frac{3}{16}$
$s i n^{- 1} (s i n x) + c o s^{- 1} (c o s y)$ to be integer $x \in [- \frac{π}{2} \frac{π}{2}]$ and $y \in [0, π] \Rightarrow x = 1$ and y =1,2,3. required Probability = $\frac{3}{16}$