The probability that the same number appear on throwing three dice simultaneously, is

1 / 36

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5 / 36

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1 / 6

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4 / 13

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Solution

The correct option is B $1 / 36$
Total number of favourable cases $= 6$
Total number of cases $= 216$
Require probability $= \frac{6}{216} = \frac{1}{36}$

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The probability that the same number appear on throwing three dice simultaneously, is

The correct option is B 1/36Total number of favourable cases =6Total number of cases =216Require probability =6216=136

The correct option is B $1 / 36$
Total number of favourable cases $= 6$
Total number of cases $= 216$
Require probability $= \frac{6}{216} = \frac{1}{36}$