The probability that there would be $1, 2$ or $3$ persons riding a bicycle are $0.85, 0.12$ and $0.03$ respectively. The expected number of persons per bicycle is

2

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1.18

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3

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Solution

The correct option is C $1.18$
Expected number of persons per bicycle is $= 1 \times P (1) + 2 \times P (2) + 3 \times P (3)$
$= 1 \times 0.85 + 2 \times 0.12 + 3 \times 0.03$
$= 1.18$

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The probability that there would be 1,2 or 3 persons riding a bicycle are 0.85,0.12 and 0.03 respectively. The expected number of persons per bicycle is

The correct option is C 1.18Expected number of persons per bicycle is =1×P(1)+2×P(2)+3×P(3)=1×0.85+2×0.12+3×0.03=1.18

The probability that there would be $1, 2$ or $3$ persons riding a bicycle are $0.85, 0.12$ and $0.03$ respectively. The expected number of persons per bicycle is

The correct option is C $1.18$
Expected number of persons per bicycle is $= 1 \times P (1) + 2 \times P (2) + 3 \times P (3)$
$= 1 \times 0.85 + 2 \times 0.12 + 3 \times 0.03$
$= 1.18$