The probability that two integers chosen at random and their product will have the same last digit is:
A
310
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B
125
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C
415
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D
715
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Solution
The correct option is B125 The condition implies that the last digit in both the integers should be 0, 1, 5 or 6 and the probability =4(110)2=4100=125 [∴ The squares of numbers ending in 0 or 1 or 5 or 6 also end with 0 or 1 or 5 or 6 respectively]