The process on an ideal gas, shown in figure, is
(a) isothermal
(b) isobaric
(c) isochoric
(d) none of these.

Open in App

Solution

According to the graph, P is directly proportional to T.

Applying the equation of state, we get

PV = nRT
$\Rightarrow P = \frac{n R}{V} T Given : P α T This means \frac{n R}{V} is a constant . So, V is also a constant .$

Constant V implies the process is isochoric.

Thus, (c) is the correct answer.

Suggest Corrections

Similar questions

Q. A graph of pressure versus volume for an ideal gas for isochoric, isobaric, isothermal and adiabatic processes is given. Which one is for the adiabatic process?

Q. An ideal gas undergoes four different processes from the same initial state (Figure Four processes are adiabatic, isothermal, isobaric and isochoric. Out of

1, 2, 3

and

4

, which one is adiabatic?

Q. Five moles of a gas is put through a series of changes in a cyclic process as show in the graph.
Processes

A \to B, B \to C a n d C \to A

respectively are:

Q. One mole of an ideal gas is carried through a thermodynamic cycle as shown in the figure. The cyclic process consists of an isochoric, an isothermal and an adiabatic process. Find adiabatic exponent of gas :

One mole of an ideal gas is carried through a thermodynamic cycle as shown in the figure. The cyclic process consists of an isochoric, an isothermal and an adiabatic process. Find adiabatic exponent of the gas

Join BYJU'S Learning Program

The process on an ideal gas, shown in figure, is (a) isothermal (b) isobaric (c) isochoric (d) none of these.

According to the graph, P is directly proportional to T. Applying the equation of state, we get PV = nRT ⇒P=nRVTGiven: P α TThis means nRV is a constant. So, V is also a constant. Constant V implies the process is isochoric. Thus, (c) is the correct answer.

The process on an ideal gas, shown in figure, is
(a) isothermal
(b) isobaric
(c) isochoric
(d) none of these.