The product formed along with copper sulfate on reaction of copper with sulfuric acid is:

S O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

S_{2} O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

S O_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

both A and C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $S O_{2}$
$(C)$ $S O_{2}$

$R e a s o n$ : When copper is heated with conc. sulphuric acid( $H_{2} S O_{4}$ ), a redox reaction occurs and the acid gets reduced to sulphur dioxide( $S O_{2}$ ), and copper sulfate( $C u S O_{4}$ ) is also formed.
$R e a c t i o n$ : $C u$ + $2 H_{2} S O_{4}$ $\to$ $C u S O_{4}$ + $S O_{2}$ + $2 H_{2} O$

Suggest Corrections

Similar questions

C u

2.5 g

C u O + H_{2} {S O}_{4} \to {C u S O}_{4} + H_{2} O

Join BYJU'S Learning Program