You visited us 7 times! Enjoying our articles? Unlock Full Access!

Preparations and Uses of Caustic Soda

The product f...

Question

The product formed at anode and cathode, when dilute $H_{2} S O_{4}$ is electrolyzed are

S O_{2}

H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

S O_{3}

H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{2} S_{2} O_{8}

H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

O_{2}

H_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $O_{2}$ , $H_{2}$
At anode, hyroxide ions are oxidized in preference to sulfate ions as the discharge potential of sulfate ions is higher than that of hydroxide ions.
Hence, hydrogen gas is liberated at anode.
At cathode, $H^{+}$ ions are reduced to hydrogen.

Suggest Corrections

Similar questions

When the aqueous solution of $L i_{2} S O_{4}$ electrolyzed the products formed at cathode and anode respectively are

Aqueous $C u S O_{4}$ is electrolyzed using $A g$ as anode and $C u$ as cathode, then product of electrolysis at anode and cathode are, respectively

H_{2} S_{2} O_{8}

O_{2}

9.72 L

H_{2}

2.35 L O_{2}

H_{2} S_{2} O_{8}

(H_{2} S_{2} O_{8})

H_{2} S O_{4}

2 H_{2} S O_{4} \to H_{2} S_{2} O_{8} + 2 H^{+} + 2 e

O_{2}

H_{2}

0.87

H_{2}

3.36

O_{2}

H_{2} S_{2} O_{8}

Join BYJU'S Learning Program