The product formed in the following reaction will be-2 KHCO 3- H 2 SO 4-A- K 2 SO 4- CO 2B- K 2 SO 4-2 H 2 O -2 CO 2C- K 2 SO 4- H 2 OD- K 2 SO 4- H 2 S - CO 2

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Reaction of Carbonates and Bicarbonates with Dil. Sulphuric Acid

The product f...

Question

The product formed in the following reaction will be:

$2 K H C O_{3} + H_{2} S O_{4} \to$

$K_{2} S O_{4} + C O_{2}$

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$K_{2} S O_{4} + 2 H_{2} O + 2 C O_{2}$

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$K_{2} S O_{4} + H_{2} O$

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$K_{2} S O_{4} + H_{2} S + C O_{2}$

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Solution

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Similar questions

F e C_{2} O_{4} + K M n O_{4} + H_{2} S O_{4} \to F e_{2} (S O_{4})_{3} + C O_{2} + M n S O_{4} + K_{2} S O_{4} + H_{2} O

K M n O_{4} + H_{2} S O_{4} + K_{2} C_{3} O_{4} \to M n S O_{4} + C O_{2} + K_{2} S O_{4}

F e C_{2} O_{4} + K M n O_{4} + H_{2} S O_{4} \to F e_{2} (S O_{4})_{3} + C O_{2} + M n S O_{4} + K_{2} S O_{4} + H_{2} O

n -

F e C_{2} O_{4}

H_{2} S O_{4}

K O H

- 59.1 k J

Δ H

H_{2} S O_{4} + 2 K O H ⟶ K_{2} S O_{4} + 2 H_{2} O

H_{2} S O_{4}

K O H

59.1 k J

Δ H

H_{2} S O_{4} + 2 K O H ⟶ K_{2} S O_{4} + 2 H_{2} O

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