The product formed in the reaction is $B C l_{3} + H_{2} O ⟶$ Product :

H_{3} B O_{3} + H C l

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B_{2} O_{3} + H O C l

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B_{2} H_{6} + H C l

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no reaction

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Solution

The correct option is B $H_{3} B O_{3} + H C l$
$B C l_{3} + 3 H_{2} O \to H_{3} B O_{3} + 3 H C l$
The products formed in the reaction are $H_{3} B O_{3} + 3 H C l$ .
Hence, option A is correct.

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Similar questions

What is the product of the reaction of $H_{2} O_{2}$ with $C l_{2}$ ?

H_{2}

(B_{2} H_{6})

O_{2}

H_{2} O

N a_{2} C O_{3} + H C l \to

B_{2} H_{6} + 2 K O H + 2 X \to 2 Y + 6 H_{2},

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