The product formed when bromobenzene reacts with benzenediazonium chloride in presence of NaOH is :

p-bromodiphenyl

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p-bromoazobenzene

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p,p'-dibromodiphenyl

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diphenyl

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Solution

The correct option is D p-bromoazobenzene
As refer to the IMAGE $01$ , the mechanism is shown in the IMAGE $02$ means Bromobenzene on reaction with diazonium chloride in presence of basic medium produce $p - b r o m o$ $a z o b e n z e n e$

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