The product formed when $H_{2} O_{2}$ reacts with acidified $K_{2} C r_{2} O_{7}$ is:

K_{2} C r_{2} O_{4}

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C r O_{3}

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C r (O H)_{3}

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C r O_{5}

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Solution

The correct option is D $C r O_{5}$

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Similar questions

H_{2} O_{2}

K_{2} C r_{2} O_{7}

C r O_{5}

K_{2} C r_{2} O_{7}

H_{2} O_{2}

Acidified solution of chromic acid on treatment with $H_{2} O_{2}$ gives blue colour which is due to -

H_{2} O_{2}

K_{2} C r_{2} O_{7}

K_{2} C r_{2} O_{7}

H_{2} S O_{4}

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