Question

The product obtained by heating diethyl ether with $HI$ is:

• A. $C_2{H}_{5}I$
• B. $C_2{H}_{5}OH$
• C. $C_2{H}_{5}OH+C_2{H}_{5}I$
• D. $C_2{H}_5-C_2{H}_5$

Answer 1

The correct option is C $C_2{H}_{5}OH+C_2{H}_{5}I$

Step (1) $\to$ Protonation

Step (2) $\to$ $S{N}_2$ reaction

Bond Formed Bond Breaks

A$\to O-H$ $B\to H-I$

$C\to C-I$ $D\to C-OH$