Question

The product obtained when one mole of diborane reacts with two mole of $N{H}_3$ at high temperature ?

• A. $B_2{H}_6.2N{H}_3$
• B. $B_3{N}_3{H}_6$
• C. $(BN{)}_x$
• D. $\left[B{H}_2\right(N{H}_3{)}_2{]}^{+}B{H}_4^{-}$

Answer 1

Answer: (B)

$B_3{N}_3{H}_6$

Diborane react with ammonia

$3B_2{H}_6+6N{H}_3\to 2B_3{N}_3{H}_6+12H_2$

So the ratio of combination of $B_2{H}_6$ and $N{H}_3$ is $1:2$

Hence option B is correct answer.