Question

Question 7

The product of 3 and 4 $\frac{2}{5}$ is
(a) $17\frac{2}{5}$
(b) $\frac{24}{5}$
(c) $13\frac{1}{5}$
(d) $5\frac{1}{13}$

Answer 1

Given $3\times 4\frac{2}{5}\because 4\frac{2}{5}=\frac{(4\times 5)+2}{5}=\frac{22}{5}\therefore 3\times 4\frac{2}{5}=3\times \frac{22}{5}=\frac{66}{5}=13\frac{1}{5}$
Hence the product of 3 and $4\frac{2}{5}$ is $13\frac{1}{5}$