Question

Question 16

The product of $7and6\frac{3}{4}$ is

(a) $42\frac{1}{4}$
(b) $47\frac{1}{4}$
(c) $42\frac{3}{4}$
(d) $47\frac{3}{4}$

Answer 1

Given $7\times \frac{3}{4}$
$\because 6\frac{3}{4}=\frac{(6\times 4)+3}{4}=\frac{24+3}{4}=\frac{27}{4}\therefore 7\times 6\frac{3}{4}=7\times \frac{27}{4}=\frac{189}{4}=47\frac{1}{4}$
Hence , the product of 7 and $6\frac{3}{4}$ is $47\frac{1}{4}$