The product of $(7 x - 4 y)$ and $(3 x - 7 y)$ is .

21 x^{2} + 28 y^{2} + 61 x y

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21 x^{2} - 28 y^{2} - 61 x y

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21 x^{2} + 28 y^{2} - 61 x y

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21 x^{2} + 28 y^{2} - 37 x y

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Solution

The correct option is C $21 x^{2} + 28 y^{2} - 61 x y$
To find: The product of $(7 x - 4 y) (3 x - 7 y)$ .
By distrivutive property, we know that, $(a + b) (c + d) = a (c + d) + b (c + d)$
On applying this, we get,
$(7 x - 4 y) (3 x - 7 y)$
$= [7 x \times (3 x - 7 y)] - [4 y \times (3 x - 7 y)]$
$= 21 x^{2} - 49 x y - 12 x y + 28 y^{2}$
$= 21 x^{2} + 28 y^{2} - 61 x y$

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Similar questions

(7 x - 4 y)

(3 x - 7 y)

$Find the product of (7 x - 4 y) and (3 x - 7 y) .$

The product of $7 x - 4 y$ and $3 x - 7 y$ is

f (2 x + 3 y, 2 x - 7 y) = 20 x

f (x, y)

13 x y, 7 x, 8 y, - x^{2} y^{2}, - 7 x y, - 200 x, 12 x^{2} y^{2}, 21, - 7 y, - 5 x, 12 x y, - 3 x, 4 y

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