The product of -7x - 4y- and -3x - 7y- is nbsp-21x-2-28y-2-61xy21x-2-28y-2-61xy21x-2-28y-2-61xy21x-2-28y-2-37xy

The correct option is C 21x^2+28y^2 61xyTo find: The product of nbsp;(7x 4y) (3x 7y) . By distrivutive property, we know that, (a+b)(c +d )= a(c +d )+b(c ...

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Byju's Answer

Standard VII

Mathematics

Multiplication of a Binomial by a Binomial

The product o...

Question

The product of $(7 x - 4 y)$ and $(3 x - 7 y)$ is .

21 x^{2} + 28 y^{2} + 61 x y

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21 x^{2} - 28 y^{2} - 61 x y

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21 x^{2} + 28 y^{2} - 61 x y

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21 x^{2} + 28 y^{2} - 37 x y

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Solution

The correct option is C $21 x^{2} + 28 y^{2} - 61 x y$
To find: The product of $(7 x - 4 y) (3 x - 7 y)$ .
By distrivutive property, we know that, $(a + b) (c + d) = a (c + d) + b (c + d)$
On applying this, we get,
$(7 x - 4 y) (3 x - 7 y)$
$= [7 x \times (3 x - 7 y)] - [4 y \times (3 x - 7 y)]$
$= 21 x^{2} - 49 x y - 12 x y + 28 y^{2}$
$= 21 x^{2} + 28 y^{2} - 61 x y$

Suggest Corrections

The product of (7x−4y) and (3x−7y) is .

The correct option is C 21x2+28y2−61xyTo find: The product of (7x−4y)(3x−7y) . By distrivutive property, we know that, (a+b)(c+d)=a(c+d)+b(c+d) On applying this, we get, (7x−4y)(3x−7y) =[7x×(3x−7y)]−[4y×(3x−7y)] =21x2−49xy−12xy+28y2 =21x2+28y2−61xy

The product of $(7 x - 4 y)$ and $(3 x - 7 y)$ is .