The product of (8x-4y) and (2x-9y) is

$16 x^{2} + 36 y^{2} - 40 x y$

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$16 x^{2} + 36 y^{2} - 80 x y$

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$16 x^{2} + 36 y^{2} - 160 x y$

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$32 x^{2} + 36 y^{2} - 80 x y$

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Solution

The correct option is B
$16 x^{2} + 36 y^{2} - 80 x y$

The given expression is

$(8 x - 4 y)$ and $(2 x - 9 y)$

$\Rightarrow$ $16 x^{2} - 72 x y - 8 x y + 36 y^{2}$

$\Rightarrow$ $16 x^{2} + 36 y^{2} - 80 x y$

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Similar questions

4 x^{2} + 9 y^{2} - 8 x - 36 y + 15 = 0

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3 x - 4 y + 6 z

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(8 x + 9 y) (8 x - 9 y) =

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8 x - 9 y = 20

7 x - 10 y = 9

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