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Preparations and Uses of Sodium Bicarbonate and Common Salt

The product o...

Question

The product of electrolysis of conc. solution of common salt is?

N a + C l_{2}

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H_{2} + O_{2}

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N a O H + H_{2} + C l_{2}

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N a + C l_{2} + O_{2}

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Solution

The correct option is C $N a O H + H_{2} + C l_{2}$

The ionization of salt:

$N a C l \to N a^{+} + C l^{-}$

The half-reaction at the cathode is:

$H_{2} O + 2 e^{-} \to H_{2} + 2 O H^{-}$
Here, the reduction is taking place.

The half-reaction at the anode is:

$2 C l^{-} \to C l_{2} + 1 e^{-}$
Here, oxidation is taking place.

The overall reaction is as follows:

$N a C l + H_{2} O \to N a^{+} + O H^{-} + H_{2} + C l_{2}$ .

Hence, option $C$ is correct.

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Similar questions

Given are the reactions occuring during the electrolysis of sodium chloride solution:

$2 C l^{-} \to C l_{2} + 2 e^{-}$
$2 H_{2} O + 2 e^{-} \to H_{2} + 2 O H^{-}$

Which of the following is correct regarding liberation of electrolytic products?

N a C l

C l_{2}

N a O H

H_{2}

C_{6} H_{12} O_{6} ⟶ C_{2} H_{5} O H + C O_{2}

F e + O_{2} ⟶ {F e}_{2} O_{3}

N H_{3} + {C l}_{2} ⟶ N_{2} H_{4} + N H_{4} C l

N a + H_{2} O ⟶ N a O H + H_{2}

C a C O_{3} + H C l \to C a C l_{2} + C O_{2} ↑ + H_{2} O

N a + H_{2} O \to N a O H + H_{2} ↑

(N H_{4})_{2} S O_{4} + C a (O H)_{2} \to C a S O_{4} + N H_{3} ↑ + H_{2} O

H g (N O_{3})_{2} \to H g + N O_{2} ↑ + O_{2} ↑

P b_{3} O_{4} + H C l \to P b C l_{2} + C l_{2} ↑ + H_{2} O

N a C l

2 O H^{-} + C l_{2} \to 2 O C l^{-} + H_{2} O

2 N a + 2 H_{2} O \to 2 N a O H + H_{2}

4 O H^{-} \to O_{2} + 2 H_{2} + 4 e^{-}

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