Question

The product of five consecutive numbers is always divisible by ?

• A. $60$
• B. $12$
• C. $120$
• D. $72$

Answer 1

Answer: (C)

$120$

Solution:

The product $\left(n\right)$ of any $5$ consecutive numbers will always be divisible by $120$ and its factors.

$n(n+1)(n+2)(n+3)(n+4)$

$5\times 4\times 3\times 2=120$

Answer C: