Question

The product of $\left(\frac{4p}{5}-3\right)$ and $\left(\frac{5p}{8}-6\right)$ is:

Answer 1

To find: $(\frac{4p}{5}-3)\times (\frac{5p}{8}-6)$

$=\frac{4p\times 5p}{5\times 8}-\frac{4p\times 6}{5}-\frac{3\times 5p}{8}+(-3)\times (-6)$.

$=\frac{p^2}{2}-\frac{24p}{5}-\frac{15p}{8}+18$.

$=\frac{p^2}{2}-\frac{(24\times 8+15\times 5)p}{5\times 8}+18$.

$=\frac{p^2}{2}-\frac{267}{40}p+18$.