The product of n positive numbers is unity, then their sum will be
A
a positive integer
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B
divisible by ′n′
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C
equal to ′n2′
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D
never less than ′n′
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Solution
The correct option is D never less than ′n′ Let x1,x2,x3,...,xn be n positive numbers
Now, x1x2x3...xn=1
Using AM≥GM ⇒x1+x2+x3+...+xnn≥(x1x2x3...xn)1n ⇒x1+x2+x3+...+xn≥n