The product of oxidation of I -with MnO 4-in alkaline medium is-A- IO 3-B- I 2C- IO -D- IO 4-

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Potassium Permanganate

The product o...

Question

The product of oxidation of $I^{-}$ with $M n O_{4}^{-}$ in alkaline medium is:

I O_{3}^{-}

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I_{2}

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I O^{-}

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I O_{4}^{-}

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I^{⊖}

M n O_{4}^{⊖}

$K M n O_{4}$ acts as an oxidizing agent in alkaline medium. When alkaline $K M n O_{4}$ is treated with KI, iodide ion is oxidized to

K M_{n} O_{4}

K M_{n} O_{4}

I^{-}

M n O_{4}^{-}

I^{-}

I^{-}

M n O_{4}^{-}

I^{-}

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