The product of oxidation of $I^{-}$ with ${M n O_{4}}^{-}$ in alkaline medium is:

{I O_{3}}^{-}

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I_{2}

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I O^{-}

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{I O_{4}}^{-}

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Solution

The correct option is A ${I O_{3}}^{-}$

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Similar questions

I^{-}

M n O_{4}^{-}

I^{⊖}

M n O_{4}^{⊖}

$K M n O_{4}$ acts as an oxidizing agent in alkaline medium. When alkaline $K M n O_{4}$ is treated with KI, iodide ion is oxidized to

K M_{n} O_{4}

K M_{n} O_{4}

{I O}_{3}^{-}, {I O}_{4}^{-}, K I

I_{2}

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