Question

The product of $\sqrt{27}$ and $\sqrt{3}$ is ____________ which is a ___________ number $9$.

• A. $\sqrt{81}$
• B. rational

Answer 1

Finding product of $\sqrt{27}$ and $\sqrt{3}$:

Given , numbers are $\sqrt{27}$and $\sqrt{3}$

we have to calculate product of $\sqrt{27}$and $\sqrt{3}$

$$\begin{gathered} \Rightarrow \sqrt{27}\times \sqrt{3}=\sqrt{27\times 3} \\ \Rightarrow \sqrt{27}\times \sqrt{3}=\sqrt{81} \end{gathered}$$

Here , $\sqrt{81}$ is a rational number because $\sqrt{81}$$=\sqrt{9\times 9}=9$, which is not an irrational number.

Hence, the product of $\sqrt{27}$ and $\sqrt{3}$ is$\sqrt{81}$ which is a rational number $9$.