Question

The product of the following monomial:
$-3a,4a,b,-6c,d$ is $72a^{2}bcd$

• A. True
• B. False

Answer 1

The correct option is A True

We multiply the given monomials $-3a,4a,b,-6c$ and $d$ as shown below:

$(-3a)\times 4a\times b\times (-6c)\times d=(-3\times a)\times 4a\times b\times (-6\times c)\times d=(-3\times 4\times (-6\left)\right)\times (a\times a)\times b\times c\times d=72\times a^2\times bcd=72a^{2}bcd$

Hence, the product of $-3a,4a,b,-6c$ and $d$ is $72a^{2}bcd$.