The product of the following reactions is (are):
$C_{2} H_{5} B r + 2 N a + C H_{3} B r dry ether \to$ ?

ethane

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propane

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butane

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ethane, propane and butane

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Solution

The correct option is D ethane, propane and butane
If two different alkyl halides are taken in wurtz reaction then alkanes with both odd and even number of C atoms are obtained.
$C_{2} H_{5} B r + 2 N a + C H_{3} - B r Dry ether - ---- \to C_{2} H_{5} - C H_{3} + C_{2} H_{5} - C_{2} H_{5} + C H_{3} - C H_{3} + 2 N a B r$
It involves radical mechanism.

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