The product of the monomials $(2 x^{4} y)$ and $(3 x^{5} y^{8})$ is :

5 x^{9} y^{9}

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6 x^{9} y^{8}

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6 x^{9} y^{9}

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5 x^{20} y^{8}

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6 x^{20} y^{8}

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Solution

The correct option is C $6 x^{9} y^{9}$
The product of monomials $2 x^{4} y$ and $3 x^{5} y^{8}$ is
$2 x^{4} y \times 3 x^{5} y^{8} = 2 (3) . x^{4} (x^{5}) . y^{1} (y^{8})$
$\Rightarrow 6 x^{4 + 5} y^{1 + 8}$
$\Rightarrow 6 x^{9} y^{9}$

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