The product of the reaction of alcoholic silver nitrate with ethyl bromide is

Ethene

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Nitroethane

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Ethane nitrite

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Ethyl alcohol

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Solution

The correct option is B Nitroethane
$C_{2} H_{5} B r + A g N O_{2} \to C_{2} H_{5} N O_{2} + A g B r$

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The final product formed when ethyl bromide reacts with excess of alcoholic KOH

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