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Foreign Invasions

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Question

The product of three geometric mean between $\frac{1}{4}$ and $4$ is

A

1

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B

14

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C

28

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D

32

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Solution

The correct option is A $1$
Product of $n$ G.M.'s between $a$ and $b$
$= (a b)^{n / 2} = {(\frac{1}{4} \times 4)}^{3 / 2} = 1$

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