Question

The product of three rational numbers is10. The first number is 2 and the second number is such that numerator is twice of first number and denominator is thrice of additive inverse of first number. Find the third number?

• A. $\frac{-15}{2}$
• B. $\frac{15}{2}$
• C. $\frac{10}{3}$
• D. None of these

Answer 1

The correct option is A

$\frac{-15}{2}$

First number = 2
Second number $=\frac{4\left(twicethefirstnumber\right)}{-6\left(thricetheadditiveinverseoffirstnumber\right)}$
Third number $=2\times \left(\frac{4}{-6}\right)\times X=10$
$x=\frac{-15}{2}$