Question

The product of two consecutive even numbers is $7568$. What is $150\%$ of the sum of the two numbers?

• A. $204$
• B. $261$
• C. $304$
• D. $198$
• E. Number of these

Answer 1

The correct option is B $261$

As the square root $7568$ lies between $2$ even numbers $86$ and $88$,

$7568=86\times 88$

Thus the two consecutive even numbers whose product is $7568$ are $86$ and $88$

.Required number $=\frac{150}{100}(86+88)=261$.