Question

The product of two consecutive integers is $156$. Find the integers.

• A. $10$ and $13$
• B. $12$ and $13$
• C. $12$ and $11$
• D. $1$`and $13$

Answer 1

The correct option is B $12$ and $13$

Let $x$ be the first integer and $x+1$ be the second integer.
Product of these two integers $=x(x+1)=156$
$x^2+x-156=0$
$(x-12)(x+13)=0$
$x=12$ or $x=-13$
The first integer is $12$ and the second integer is $x+1=13$
Therefore, the two integers are $12$ and $13$.