Question

The product of two consecutive integers is $600$. Find the second integer.

• A. $24$
• B. $23$
• C. $25$
• D. $26$

Answer 1

Answer: (C)

$25$

Let $x$ be the first integer and $x+1$ be the second integer

Product of these two integers $=x(x+1)=600$

$\Rightarrow x^2+x-600=0$

$\Rightarrow (x-24)(x+25)=0$

$\Rightarrow x=24$ or $x=-25$

$\therefore$ The first integer is $24$.
So, the second integer will be $x+1=25$.