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Quadratic Equations

The product o...

Question

The product of two consecutive natural numbers is $12$ . The equation form of this statement is

x^{2} + 2 x - 12 = 0

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x^{2} + 1 x - 12 = 0

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x^{2} + 1 x + 12 = 0

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x^{2} + 2 x + 12

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Solution

The correct option is B $x^{2} + 1 x - 12 = 0$
Let $x$ be any natural number, then $x$ and $x + 1$ are two consecutive natural numbers.
Given : Product of two natural numbers is $12$
$⟹$ $x (x + 1) = 12$
$⟹$ $x^{2} + x = 12$
$∴$ $x^{2} + x - 12 = 0$

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