The product of two consecutive natural numbers is 72. Frame the quadratic equation. $[2]$

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Solution

If a natural number is $x$ , the next natural number is greater than $x$ by 1 and hence $x$ +1.

The product is $x$ ( $x$ +1) = $x^{2}$ + $x$ $[1 m a r k]$

Therefore $x^{2}$ + $x$ $= 72$

$\Rightarrow x^{2} + x - 72 = 0$ $[1 m a r k]$

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The product of two consecutive natural numbers is 72. Frame the quadratic equation. [2]

If a natural number is x, the next natural number is greater than xby 1 and hence x+1. The product is x(x+1) =x2+ x [1mark] Therefore x2+ x =72 ⇒ x2+x−72=0 [1mark]

The product of two consecutive natural numbers is 72. Frame the quadratic equation. $[2]$

If a natural number is $x$ , the next natural number is greater than $x$ by 1 and hence $x$ +1.

The product is $x$ ( $x$ +1) = $x^{2}$ + $x$ $[1 m a r k]$

Therefore $x^{2}$ + $x$ $= 72$

$\Rightarrow x^{2} + x - 72 = 0$ $[1 m a r k]$