Question

The product of two consecutive negative integers is 1122. What are the numbers?

• A. $-22,-23$
• B. $-33,-34$
• C. $-11,-12$
• D. $Noneofthese$

Answer 1

The correct option is B $-33,-34$

Given that, the product of two consecutive negative integers is $1122$.

To find out: The numbers.

Let the required numbers be $n$ and $n+1$.

$\therefore n(n+1)=1122$

$n^2+n-1122=0$

$(n+34)(n-33)=0$

$n=-34,33$

Since, $n$ is negative, therefore, $n=-34$

Hence, $n+1=-33$

Thus, the required numbers are $-33$ and $-34$.