wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The product of two numbers is 14m6n321m4n5+7m5n4. If one number is 7m2n2, then the other number is


A

2m4n3m2n3+m3n2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

2m4n3m2n3+m3n2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

2m4n+3m2n3+m3n2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

2m4n3m2n3m3n2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

2m4n3m2n3+m3n2


Tthe product of two numbers is 14m6n321m4n5+7m5n4.

One number = 7m2n2

Then second number is 14m6n321m4n5+7m5n47m2n2

We shall perform the above division as follows:

14m6n321m4n5+7m5n47m2n2

= 14m6n37m2n221m4n57m2n2+7m5n47m2n2

= 2m4n3m2n3+m3n2


flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Multiplication of Algebraic Expressions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon