Question

The product of two numbers is $336$. Their sum exceeds their difference by $32$. What are the numbers?

• A. $42,8$
• B. $48,7$
• C. $24,14$
• D. $21,16$

Answer 1

The correct option is D $21,16$

Let x and y be the numbers Then
$xy=336$ and $(x+y)-(x-y)=32$
$\Rightarrow$ $y=16$
$\therefore x=\frac{336}{16}=21$