Question

The product of two numbers is $87\frac{3}{4}$. If one of the numbers is $4\frac{7}{8}$,find the other?

Answer 1

Step 1: Given:

Product of two numbers is $87\frac{3}{4}$ and one of them is $4\frac{7}{8}$

Convert mixed fraction into simple fraction,

$87\frac{3}{4}=\frac{87\times 4+3}{4}=\frac{351}{4}$ and $4\frac{7}{8}=\frac{4\times 8+7}{8}=\frac{39}{8}$

Product of two numbers is $\frac{351}{4}$ and one of them is $\frac{39}{8}$

Step 2:- Finding the other number,

Let suppose the another number is $y$

Then according to the given condition,

⇒ $\frac{39}{8}\times y=\frac{351}{4}$

= $y=\frac{351}{4}÷\frac{39}{8}$

Converting the division sign into multiplication by taking reciprocal of $\frac{39}{8}$ i.e. $\frac{8}{39}$

⇒ $y=\frac{351}{4}\times \frac{8}{39}$

⇒ $y=\frac{351\times 8}{4\times 39}$

⇒ $y=18$

Therefore, the other number is $18$.