Question

The product of two numbers whose HCF is 18 is 5832 How many pairs of numbers satisfy the above conditions?

• A. One
• B. Two
• C. Three
• D. None of these

Answer 1

Answer: (B)

Two

Let the numbers be $18x;18y$, where $x,y$ are co-prime to each other.
Then $18x\times 18y=5832$
$=>xy=18$
Now, we need to find co-prime numbers whose product is $18$
$18=2\times 3^2$
Therefore co-prime pairs will be $(1,18);(2,9)$
Therefore, only two pairs of such numbers satisfy the given condition.