Question

The product of two positive integers is $936$. Find the greater number, if the integers are in the ratio $13:18.$

• A. $27$
• B. $31$
• C. $36$
• D. $41$

Answer 1

The correct option is C $36$

Let the two positive integers be $13x$ and $18x.$
Their product is $936.$

$\therefore 13x\times 18x=936$

$\Rightarrow x^2=\frac{936}{13\times 18}=4$

$\Rightarrow x=2$
Then two positive integers are $26$ and $36.$
$\therefore$ The greater number is $36.$