Question

The product of two positive numbers is 120 and when their squares are added, we get 289. The sum of the numbers is:

• A. 20
• B. 23
• C. 169
• D. 179
• E. 186

Answer 1

The correct option is B

23

Let the numbers be x and y.

Then, xy = 120 and $x^2+y^2=289.$ $\therefore {\left(x+y\right)}^2=x^2+y^2+2xy=289+240=529.$ $\therefore x+y=\sqrt{529}=23.$