Question

The product of two rational numbers $\frac{-9}{16}$. If one of the numbers is $\frac{-4}{3}$ then the other number is:

• A. $\frac{36}{48}$
• B. $\frac{25}{64}$
• C. $\frac{27}{49}$
• D. $\frac{27}{64}$

Answer 1

Answer: (D)

$\frac{27}{64}$

Let the required no. be $x$.

$\therefore x\times \frac{-4}{3}=\frac{-9}{16}$

$\Rightarrow x=\frac{-9/16}{-4/3}=\frac{-9}{16}\times \frac{-3}{4}=\frac{27}{64}$