Question

The product of two rational numbers is $\frac{-16}{9}$. If one of the numbers is $\frac{-4}{3}$, find the other.

Answer 1

$$\begin{gathered} \mathrm{Let}\mathrm{the}\mathrm{number}\mathrm{be}\mathrm{x}. \\ \mathrm{Now}, \\ \mathrm{x}\times \frac{-4}{3}=\frac{-16}{9} \\ \Rightarrow \mathrm{x}=\frac{-16}{9}÷\frac{-4}{3} \\ \Rightarrow \mathrm{x}=\frac{-16}{9}\times \frac{3}{-4} \\ \Rightarrow \mathrm{x}=\frac{-16\times 3}{9\times (-4)} \\ \Rightarrow \mathrm{x}=\frac{48}{36} \\ \Rightarrow \mathrm{x}=\frac{4}{3} \end{gathered}$$.