Question

The product of two rational numbers is $\frac{-8}{9}.$ If one of the numbers is $\frac{-4}{15},$ find the other.

Answer 1

$$\begin{gathered} \mathrm{Let}\mathrm{the}\mathrm{other}\mathrm{number}be\mathrm{x}. \\ \therefore \mathrm{x}\times \frac{-4}{15}=\frac{-8}{9} \\ \mathrm{or}\mathrm{x}=\frac{-8}{9}÷\frac{-4}{15} \\ \mathrm{or}\mathrm{x}=\frac{-8}{9}\times \frac{15}{-4} \\ \mathrm{or}\mathrm{x}=\frac{10}{3} \\ Thus,\mathrm{the}\mathrm{other}\mathrm{number}\mathrm{is}\frac{10}{3}. \end{gathered}$$