Question

The product of two whole numbers is $13$. What is the sum of the squares of their reciprocals?

• A. $\frac{170}{169}$
• B. $\frac{173}{169}$
• C. $\frac{171}{169}$
• D. $\frac{172}{169}$

Answer 1

The correct option is A $\frac{170}{169}$

Since $13$ is a prime number, the two whole numbers whose product is $13$, are $1$ and $13$.
Sum of the square of reciprocals $=1+\frac{1}{{13}^2}$$=1+\frac{1}{169}$$=\frac{170}{169}$