Question

The product of Young’s modulus of the material of the wire with its cross -sectional area is equal to its length. Find the parameters representing \(x\) and \(y-\text {axes} \) of the curve as shown:

Answer 1

Given,
\(YA=l\)
Therefore
\(Y=\dfrac{\text {stress}}{\text{strain}}\)
\(Y=\dfrac{\left( \dfrac{W}{A} \right)}{\left( \dfrac{\Delta l}{l} \right)}\)
\(\Delta l=\left( \dfrac{l}{YA} \right)W\)
\(\dfrac{\Delta l}{W}=1\) (given \(YA=l\))